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integration by parts method

evaluate .∫ (x²) sin x  dx ,.∫ x ²cos(mx) dx using integration by parts

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evaluate .∫ (x²) sin x  dx using integration by parts

take 
(x²) as the first function and sinx as the second function because
the differentiation of  (x²) give 2x and then  2  in a couple of steps
apply method of integration by parts

integration formula

integration by parts
integration by parts

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problem 2

 evaluate .∫ x ²cos(mx) dx using integration by parts

take  (x²) as the first function and cosmx  as the second function
and apply method of integration by parts
integration by parts method

some problems from integral calculus

* Integrate e^{x^(1/3)}dx

* evaluate integral of [e^(-x) +1] ^2

*evaluate ∫ (sin 3x)^4 dx with limits 0 to pi

* evaluate the integral of sqrt(tan  x)

* evaluate integral of { sqrt{1+(x^2)} } / {x^2}
using integration by parts


*∫ sec³x dx using integration by parts

*integral of (e^(ax) )  cosbx using integration by parts


Area using integral

* evaluate the area of an ellipse (x² /a²) + (y²/b²) =1 using integration

* find the area between y² = x and x² =y

* find the area bounded b y =x² and y = 3x

other questions and problems:


*integral calculus integration formula





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trigonometric identity and ratio of  certain standard angles

*list of differentiation formula     *integral calculus integration formula
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