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power series expansion for y = arctan(x) in powers of x
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find a power series expansion for y = arctan(x) in powers of x
or find a maclaurin series for arc tan(x)

y =
arctan(x) find y(0)
y1 = 1 / [ 1 + x^2] find y1(0) =
now expand y1 = 
[ 1 + x^2]^(-1) as a binomial series
before differentiating further
then continue and find y2(0) ... and use in mclaurin series.

maclaurin series for arc tan(x)





                                                      


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